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That wouldn’t change the graph’s gist, though
That wouldn’t change the graph’s gist, though
I am Turkish. They are doing this becuse it is one of the weird shows of extreme right wing
I tried torch compile before, it is nice but resolving cpp errors in Python is a pain. I am more excited about mojo
!interestingasfuck
Chill man, getting downvoted sometimes means people disagree with you, as you said; not that your comment was shitty.
Get a real computer
I have been using Firefox with ublock for a very long time. I forgot how they looked like
Without condition would be more technically correct term but yes
A/100×B=A×B/100
Just count the number of possibilities. If you change there there two possible first choices to win + if you do not change 1 possible choice to win = 3. If you change there is one possible first choice to lose + if you do not change there two possible first choices to lose=3 P(x1)=P(x1’) = 3/6
First, fuck you! I couldn’t sleep. The possibility to win the car when you change is the possibility of your first choice to be goat, which is 2/3, because you only win when your first choice is goat when you always change.
x1: you win
x2: you change
x3: you pick goat at first choice
P(x1|x2,x3)=1 P(x1)=1/2 P(x3)=2/3 P(x2)=1/2
P(x1|x2) =?
Chain theory of probability:
P(x1,x2,x3)=P(x3|x1,x2)P(x1|x2)P(x2)=P(x1|x2,x3)P(x2|x3)P(x3)
From Bayes theorem: P(x3|x1,x2)= P(x1|x2,x3)P(x2)/P(x1) =1
x2 and x3 are independent P(x2|x3)=P(x2)
P(x1| x2)=P(x3)=2/3 P(x2|x1)=P(x1|x2)P(x2)/P(X1)=P(x1|x2)
P(x1=1|x2=0) = 1- P(x1=1|x2=1) = 1\3 is the probability to win if u do not change.
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deleted by creator
Does it have system tray for gnu linux?
I didn’t understand. Aren’t all ports go through the encrypted traffic once I start a vpn?
For games rutor.info is very up todaye. It is in Russian but name of torrents are in English. Also it doesn’t use https so always connect to it using Tor browser
That is a lot of money. Any idea how many they are?